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CMC Medical CMC-Medical Ludhiana Solved Paper-2010

  • question_answer
    A wire of length L carries a current i. It is bent in the form of a circle. The magnetic moment of current loop (in \[A\text{-}{{m}^{2}}\]) is

    A)  \[\frac{i{{L}^{2}}}{4{{\pi }^{2}}}\]                            

    B)  \[i\pi {{L}^{2}}\]

    C)  \[\frac{i{{L}^{2}}}{4\pi }\]                                           

    D)  \[4\pi i{{L}^{2}}\]

    Correct Answer: C

    Solution :

                    Magnetic moment, \[M=IA\] Length of wire is L. \[\therefore \]  \[2\pi r=L\]                 \[r=\frac{L}{2\pi }\] \[\therefore \]  \[M=I\pi {{r}^{2}}\]                      \[=I\frac{\pi {{L}^{2}}}{4{{\pi }^{2}}}\]                      \[=\frac{I{{L}^{2}}}{4\pi }\]


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