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CMC Medical CMC-Medical Ludhiana Solved Paper-2010

  • question_answer
    A straight section PQ of a circuit lies along x-axis at \[x=-\frac{a}{2}\,\,\,to\,\,\,x=+\frac{a}{2}\] and carries a steady current (i), the magnetic field due to section PQ at a point x = + a will be

    A)  proportional to z            

    B)  proportional to a2

    C)  proportional to \[\frac{1}{a}\]  

    D)  equal to zero

    Correct Answer: D

    Solution :

                     From Biot Savarts law, magnetic field at point R due to a straight wire \[B=\frac{{{\mu }_{0}}}{4\pi }\frac{i\Delta l\sin \theta }{{{r}^{2}}}\] but         \[\theta =0\] \[\therefore \]  \[B=0\]


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