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CMC Medical CMC-Medical Ludhiana Solved Paper-2011

  • question_answer
    At a place, horizontal component of earths magnetic field is \[\sqrt{3}\]times the vertical component. The angle of dip at that place is

    A)  \[75{}^\circ \]                                  

    B)  \[60{}^\circ \]

    C)  \[45{}^\circ \]                                  

    D)  \[30{}^\circ \]

    Correct Answer: D

    Solution :

                    Given, \[H=\sqrt{3}\,V\] Angle of dip, \[\delta ={{\tan }^{-1}}\left( \frac{V}{H} \right)\] \[={{\tan }^{-1}}\left( \frac{V}{\sqrt{3}H} \right)\] \[={{\tan }^{-1}}\left( \frac{1}{\sqrt{3}} \right)=30{}^\circ \]


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