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CMC Medical CMC-Medical Ludhiana Solved Paper-2011

  • question_answer
    A crystal has bcc structure and its lattice constant is 3.6 \[\overset{\text{o}}{\mathop{\text{A}}}\,\]. What is the atomic radius?

    A)  3.6 \[\overset{\text{o}}{\mathop{\text{A}}}\,\]              

    B)  1.8 \[\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C)  1.27 \[\overset{\text{o}}{\mathop{\text{A}}}\,\]          

    D)  1.56 \[\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: D

    Solution :

                    Atomic radius for bcc structure \[r=\frac{a\sqrt{3}}{4}=\frac{3.6\sqrt{3}}{4}=1.56\,\overset{\text{o}}{\mathop{\text{A}}}\,\]


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