CMC Medical CMC-Medical Ludhiana Solved Paper-2011

  • question_answer
    Potential energy in a spring when stretched by 2 cm, is U. Its potential energy, when stretched by 10 cm is

    A)  \[\frac{U}{25}\]                                              

    B)  \[\frac{U}{5}\]

    C)  \[25U\]                                               

    D)  \[5U\]

    Correct Answer: A

    Solution :

                    The relation for potential energy is \[U=\frac{1}{2}m{{\omega }^{2}}{{y}^{2}}\] \[U\propto {{y}^{2}}\] \[\frac{{{U}_{1}}}{{{U}_{2}}}={{\left( \frac{{{y}_{1}}}{{{y}_{2}}} \right)}^{2}}\] \[\frac{U}{{{U}_{2}}}={{\left( \frac{2}{10} \right)}^{2}}=\frac{4}{100}\] \[{{U}_{2}}=25\,\,U\]


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