A) 2
B) 0
C) 3
D) 1
Correct Answer: C
Solution :
\[A\xrightarrow{{}}B\] \[\text{Rate}=k\,{{[A]}^{n}}\] \[{{\text{(Rate)}}_{1}}=k{{(0.05)}^{n}}=2\times {{10}^{-3}}\] ?(i) \[{{\text{(Rate)}}_{2}}=k{{(0.01)}^{n}}=1.6\times {{10}^{-2}}\] ?(ii) Dividing the Eq. (ii) by Eq. (i). \[\frac{{{(Rate)}_{2}}}{{{(Rate)}_{1}}}=\frac{k{{(0.1)}^{n}}}{k{{(0.05)}^{n}}}=\frac{1.6\times {{10}^{-2}}}{2\times {{10}^{-3}}}\] \[{{(2)}^{n}}=8\] or \[{{(2)}^{n}}={{2}^{3}}\] \[\therefore \] \[n=3\]You need to login to perform this action.
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