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CMC Medical CMC-Medical Ludhiana Solved Paper-2011

  • question_answer
    A \[100\mu \]F capacitor is to have an energy content of 50 J in order to operate a flash lamp. The voltage required to charge the capacitor is

    A)  500 V 

    B)  1000 V

    C)  1500 V                                 

    D)  2000V

    Correct Answer: B

    Solution :

                                    \[E=\frac{1}{2}e{{V}^{2}}\] \[\therefore \]  \[50=\frac{1}{2}\times 100\times {{10}^{-6}}\times {{V}^{2}}\] \[{{V}^{2}}={{10}^{6}}V\] \[V=1000\,V\]


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