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CMC Medical CMC-Medical Ludhiana Solved Paper-2012

  • question_answer
    In case of a bcc lattice, the nearest distance between two atoms is equal to

    A)  \[\frac{a}{\sqrt{2}}\]                                    

    B)  \[\frac{a\sqrt{2}}{3}\]

    C)  \[\frac{a\sqrt{3}}{2}\]                  

    D)   \[a\sqrt{3}\]

    Correct Answer: C

    Solution :

                    The nearest distance between two atoms for a bcc lattice \[=2\times \]atomic radius \[=2\times \left( \frac{\sqrt{3}\,a}{4} \right)=\frac{a\sqrt{3}}{2}\]


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