CMC Medical CMC-Medical Ludhiana Solved Paper-2012

  • question_answer
    If \[{{\mu }_{0}}\] and \[{{\varepsilon }_{0}}\] denote the permeability and permittivity of free space, then the dimensions of \[{{\mu }_{0}}{{\varepsilon }_{0}}\] are

    A)  \[[{{M}^{0}}{{L}^{-2}}{{T}^{2}}]\]                            

    B)  \[[L{{T}^{-1}}]\]

    C)  \[[{{M}^{-1}}{{L}^{-3}}{{Q}^{2}}{{T}^{2}}]\]        

    D)  \[[{{M}^{-2}}{{L}^{-1}}{{I}^{2}}{{T}^{-2}}]\]

    Correct Answer: A

    Solution :

                    We know that, \[c=\frac{1}{\sqrt{{{\mu }_{0}}{{\varepsilon }_{0}}}}\] (where c is the velocity of light) \[\Rightarrow \]               \[{{\mu }_{0}}{{\varepsilon }_{0}}=\frac{1}{{{c}^{2}}}\] \[\therefore \]  \[[{{\mu }_{0}}{{\varepsilon }_{0}}]=[{{L}^{-2}}{{T}^{2}}]\]


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