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CMC Medical CMC-Medical Ludhiana Solved Paper-2012

  • question_answer
    \[C{{l}_{2}}+{{H}_{2}}S2HCl+S.\] In this chemicals reaction changes in oxidation number of sulphur is

    A)  0 to 2                                   

    B)  -2 to 0

    C)  2 to 0                                   

    D)  -2 to -1

    Correct Answer: B

    Solution :

                    \[C{{l}_{2}}+{{H}_{2}}S2HCl+S\] Let the oxidation number of S in \[{{H}_{2}}S=x\] \[2\,(+1)+x=0\]      \[+2+x=0\]                 \[x=-\,2\] oxidation number of S in s = 0 Thus, in reaction, oxidation number of sulphur changes from -2 to 0.


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