A) \[1.4\times {{10}^{-19}}eV\]
B) \[1.4\times {{10}^{-19}}J\]
C) \[14\times {{10}^{-19}}J\]
D) \[2.8\times {{10}^{-19}}J\]
Correct Answer: B
Solution :
Maximum kinetic energy \[{{K}_{\max }}=\frac{hc}{\lambda }-{{W}_{0}}\] \[=\frac{6.4\times {{10}^{-34}}\times 3\times {{10}^{8}}}{6400\times {{10}^{-10}}}-1.6\times {{10}^{-19}}\] \[=1.4\times {{10}^{-19}}J\]You need to login to perform this action.
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