CMC Medical CMC-Medical Ludhiana Solved Paper-2012

  • question_answer
    How many numbers of possible stereoisomers are there of 2, 3, 4 trichloro pentanoic acid?

    A)  8                                            

    B)  12

    C)  16                                         

    D)  4

    Correct Answer: A

    Solution :

                    The structural formula of 2, 3, 4-trichloro pentanoic acid is given below. \[\underset{C{{H}_{3}}}{\overset{O}{\mathop{\underset{|}{\overset{|\,|}{\mathop{\underset{H-\,\,\,\,{{C}^{\,*}}-\,\,Cl}{\mathop{\underset{|}{\mathop{\underset{H-\,\,\,\,{{C}^{\,*}}-\,\,Cl}{\mathop{\underset{|}{\mathop{\underset{H-\,\,\,\,\,C{{\,}^{*}}-\,\,Cl}{\mathop{\underset{|}{\mathop{C}}\,}}\,}}\,}}\,}}\,}}\,}}}\,}}}\,-OH\] Number of optical active isomers\[={{2}^{n}}\]where, n = number of asymmetric carbon atom. 2, 3, 4-trichloropentanoic acid has three asymmetric carbon atoms. So, number of optical active isomers\[={{2}^{3}}\] \[\therefore \]Number of optical active isomers = 8


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