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CMC Medical CMC-Medical Ludhiana Solved Paper-2012

  • question_answer
    On oxidation of organic compound A with \[N{{a}_{2}}C{{r}_{2}}{{O}_{7}}\] and \[{{H}_{2}}S{{O}_{4}}\] gives compound B, which on reduction with \[{{H}_{2}}\] in presence of Ni catalyst gives ethyl alcohol. Give the name of compound A.

    A)  Ethanal               

    B)  Ethanol

    C)  Ethanoic acid                    

    D)  Ethene

    Correct Answer: B

    Solution :

         \[A\xrightarrow[[O]]{N{{a}_{2}}C{{r}_{2}}{{O}_{7}}/{{H}_{2}}S{{O}_{4}}}\,B\,\,\xrightarrow[{}]{{{H}_{2}}/Ni}\]Ethyl alcohol Compound B on reduction with\[{{H}_{2}}/\]in presence of Ni given ethyl alcohol it means compound B is ethanal, because aldehyde on reduction gives primary alcohol. Again compound B obtained from oxidation of A it means A is ethanol, because primary alcohol on oxidation gives aldehyde. \[\underset{(A)}{\mathop{C{{H}_{3}}-C{{H}_{2}}-OH}}\,\xrightarrow[[O]]{N{{a}_{2}}C{{r}_{2}}{{O}_{7}}/{{H}_{2}}S{{O}_{4}}}\] \[\underset{(B)}{\mathop{C{{H}_{3}}-\overset{O}{\mathop{\overset{|\,|}{\mathop{C}}\,}}\,-H}}\,\xrightarrow{{{H}_{2}}/Ni}\underset{ethyl\,\,alcohol\,\,or\,\,ethanol}{\mathop{C{{H}_{3}}-C{{H}_{2}}-OH}}\,\]


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