A) 20 J
B) - 20 J
C) 400 J
D) - 374 J
Correct Answer: B
Solution :
\[{{W}_{PQ}}=p\Delta V\] \[=100\times {{10}^{3}}(300-100)\times {{10}^{-6}}\] \[=100\times {{10}^{-3}}\times 200\] \[=20\,J\] \[{{W}_{QR}}=0\] (\[\because \]v is constant) \[{{W}_{RS}}=p\Delta V=200\times {{10}^{3}}(100-300)\times {{10}^{-6}}\] \[=-\,200\times {{10}^{3}}\times 200\] \[=-\,40\,J\] \[{{W}_{sp}}=0\] Net work done\[=20+\left( -\,40 \right)=-\,20\text{ }J\]
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