A) 3 kJ
B) 30 kJ
C) 7.2 kJ
D) 432 kJ
Correct Answer: D
Solution :
Energy drawn from the battery \[E=VIT\] \[=12\times 300\times 2\times 60\] \[=432\times {{10}^{3}}J\] \[=432\,kJ\]You need to login to perform this action.
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