A) 200
B) 100
C) 10
D) 50
Correct Answer: B
Solution :
Let the resistance of voltmeter is\[G\,\Omega \]. \[\therefore \] Total resistance of the circuit \[R=\left( \frac{G+100}{G+100}+500 \right)\,\Omega \] Total currant \[i=\frac{V}{R}\] \[=\frac{10}{\left( \frac{G\times 100}{G+100}+50 \right)}\] Voltage across 100\[\Omega \] resistance \[=i\,\,\left( \frac{G\times 100}{G+100} \right)=\frac{10}{\left[ \frac{G\times 100}{G+100}+50 \right]}\times \left( \frac{G\times 100}{G+100} \right)\] Reading of voltmeter = 5V Voltage across 100\[\Omega \] = 5V \[5=\frac{10}{\left[ \frac{G\times 100}{G+100}+50 \right]}\times \left( \frac{G\times 100}{G+100} \right)\] Or solving \[G=100\,\,\Omega \]
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