A) \[\frac{3}{4}\] of its ionisation energy
B) \[\frac{1}{2}\] of its ionisation energy
C) \[\frac{1}{4}\] of its ionisation energy
D) \[\frac{1}{9}\]of its ionisation energy
Correct Answer: A
Solution :
The required transition energy is\[\Delta E=K\left( 1-\frac{1}{4} \right)=\frac{3}{4}K=\frac{3}{4}\times \]ionisation energyYou need to login to perform this action.
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