CMC Medical CMC-Medical Ludhiana Solved Paper-2013

  • question_answer
    An electron is accelerated through a potential difference of 200 V. If \[\frac{e}{m}\]for the electron be \[1.6\times {{10}^{11}}\,C\text{/}kg\] the velocity acquired by the electron will be

    A)  \[8\times {{10}^{6}}\text{ }m\text{/}s\]              

    B)  \[8\times {{10}^{5}}\text{ }m\text{/}s\]

    C)  \[5.9\times {{10}^{6}}\text{ }m\text{/}s\]          

    D)  \[5.9\times {{10}^{5}}\text{ }m\text{/}s\]

    Correct Answer: A

    Solution :

                    \[\frac{1}{3}m{{v}^{2}}=eV\] \[{{v}^{2}}=\frac{2e}{m}V\] \[v=\sqrt{2\cdot \frac{e}{m}V}\] \[=\sqrt{2\times 1.6\times {{10}^{11}}\times 200}\] \[=20\times 4\times {{10}^{5}}=80\times {{10}^{5}}\] \[=8\times {{10}^{6}}m\text{/}s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner