A) 0.01
B) 0.02
C) 0.03
D) 0.04
Correct Answer: A
Solution :
Suppose, D be the diameter of the wire. Poissons ratio, \[\sigma =\frac{\text{Laterial}\,\,\text{strain}}{\text{Longitudinal}\,\,\text{strain}}\] \[\sigma =\frac{\frac{\Delta \,D}{D}}{\frac{\Delta \,L}{L}}\] ?(i) Here, \[\frac{\Delta L}{L}=0.025\,%\] \[=\frac{0.025}{1000}=\frac{1}{40}\] and \[\sigma =0.0\,4\] Putting the given values in Eq. (i) We obtain, \[0.4=\frac{\frac{\Delta D}{D}}{\frac{1}{40}}\] \[\frac{\Delta D}{D}=\frac{1}{40}\times 0.4=0.01%\]
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