CMC Medical CMC-Medical Ludhiana Solved Paper-2015

  • question_answer
    A rod of Span 1 m is suspended through an end and is set into oscillation with some small amplitude within the gravitational field. The time period will be

    A)  1.65                      

    B)  1.25

    C)  1.95                      

    D)  2.15

    Correct Answer: A

    Solution :

                    The oscillation will be nearly of simple harmonic nature for which time period is given by \[T=2\pi \sqrt{\frac{I}{mgl}}=2\pi \sqrt{\left( \frac{m{{l}^{2}}}{3} \right)/mgl/3}\]    \[=2\pi \sqrt{\frac{2l}{3g}}\]    \[=2\pi \sqrt{\frac{2\times 1}{3\times 9.8}}=164\,s\]


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