A) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\]
B) \[C{{H}_{3}}\overset{OH}{\mathop{\overset{\mathbf{|}}{\mathop{CH}}\,}}\,-C{{H}_{2}}CHO\]
C) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}-OH\]
D) \[C{{H}_{2}}=CH-C{{H}_{3}}\]
Correct Answer: B
Solution :
\[\underset{Ethanol}{\mathop{C{{H}_{3}}C{{H}_{2}}}}\,-OH\xrightarrow[\text{or}\,\,PCC/C{{H}_{2}}C{{l}_{2}}]{Cu/573K}C{{H}_{3}}CHO\] \[\xrightarrow[(Aldol\,condensation)]{Dil.\,NaOH}\underset{3-hydroxy\,butanal}{\mathop{C{{H}_{3}}-\overset{OH}{\mathop{\overset{\mathbf{|}}{\mathop{CH}}\,}}\,-C{{H}_{2}}CHO}}\,\]
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