A) D-glucose
B) D-ribose
C) L-glucose
D) D-fructose
Correct Answer: A
Solution :
Cellulose is a polysaccharide, having monomer unit of D-glucose units which are joined by \[\beta \]-glycosidic linkages, therefore on complete hydrolysis of cellulose, D-glucose is formed. \[\underset{Cellulose}{\mathop{{{({{C}_{6}}{{H}_{10}}{{O}_{5}})}_{n}}}}\,+n{{H}_{2}}O\xrightarrow{{{H}^{+}}}\underset{D\text{-}glucose}{\mathop{n{{C}_{6}}{{H}_{12}}{{O}_{6}}}}\,\]
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