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CMC Medical CMC-Medical VELLORE Solved Paper-2007

  • question_answer
    If 1A of current is passed through \[CuS{{O}_{4}}\]solution for 10 s, the number of copper atoms deposite at the cathode will be about

    A)  \[1.6\times {{10}^{20}}\]                            

    B)  \[8\times {{10}^{19}}\]

    C)  \[3.1\times {{10}^{19}}\]                            

    D)  \[6.2\times {{10}^{19}}\]

    Correct Answer: C

    Solution :

                     Number of Cu ions liberated is \[n=\frac{I.\,t}{e\,\text{(valence}\,\text{electron)}}\] \[n=\frac{1\times 10}{1.6\times {{10}^{-19}}\times 2}\] \[n=3.125\times {{10}^{19}}\] \[n\approx 3.1\times {{10}^{19}}\]


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