A) \[6.16\times {{10}^{14}}Hz\]
B) \[6.16\times {{10}^{13}}Hz\]
C) \[6.16\times {{10}^{10}}Hz\]
D) \[6.16\times {{10}^{16}}Hz\]
Correct Answer: A
Solution :
Wavelength of Balmer series is given by \[\frac{1}{\lambda }=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\] \[\frac{v}{c}=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\] \[(\therefore c=v\lambda )\] \[v=cR\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\] For second line of Balmer series \[{{n}_{1}}=2{{n}_{2}}=4\] \[\therefore \] \[v=3\times {{10}^{8}}\times 10967800\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{4}^{2}}} \right)\] \[=6.16\times {{10}^{14}}Hz\]
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