A) \[30{}^\circ \]
B) \[45{}^\circ \]
C) \[60{}^\circ \]
D) \[76{}^\circ \]
Correct Answer: D
Solution :
According to question, \[H=R\] \[\Rightarrow \] \[\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}=\frac{{{u}^{2}}\sin 2\theta }{g}\] \[\Rightarrow \] \[{{\sin }^{2}}\theta =2\,(sin\theta cos\theta )\] \[\Rightarrow \] \[\sin \theta =4\cos \theta \] \[(\sin \theta \ne 0)\] \[\Rightarrow \] \[\tan \theta =4\] \[\therefore \] \[\theta ={{\tan }^{-1}}(4)=75.96{}^\circ \approx 76{}^\circ \]
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