CMC Medical CMC-Medical VELLORE Solved Paper-2007

  • question_answer
    The largest and the shortest distances of the earth from the sun are \[{{r}_{1}}\] and \[{{r}_{2}}\]. Its distance from the sun when it is at the perpendicular the major axis of the orbit drawn from the sun, is

    A)  \[\frac{{{r}_{1}}+{{r}_{2}}}{4}\]                                

    B)  \[\frac{{{r}_{1}}{{r}_{2}}}{{{r}_{1}}+{{r}_{2}}}\]

    C)  \[\frac{2{{r}_{1}}{{r}_{2}}}{{{r}_{1}}+{{r}_{2}}}\]                                               

    D)  \[\frac{{{r}_{1}}+{{r}_{2}}}{3}\]

    Correct Answer: C

    Solution :

                    The equation of a general conic is \[\frac{1}{r}=\frac{1}{l}(1+e\cos \theta )\]where e is eccentricity. For ellipse, turning points are at \[\theta =0{}^\circ \] and\[\theta =180{}^\circ \] giving \[{{r}_{\min }}={{r}_{2}}\] and  \[{{r}_{\max }}={{r}_{1}}\] respectively \[\therefore \]  \[\frac{1}{{{r}_{2}}}=\frac{1}{l}(1-e)\] and        \[\frac{1}{{{r}_{1}}}=\frac{1}{l}(1+e)\] \[\therefore \]  \[\frac{1}{{{r}_{2}}}+\frac{1}{{{r}_{1}}}=\frac{2}{l}\] or            \[l=\frac{2{{r}_{1}}{{r}_{2}}}{{{r}_{1}}+{{r}_{2}}}\]


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