A) \[KMn{{O}_{4}}\](alkaline)
B) Osmium tetroxide \[(Os{{O}_{4}}\text{/}C{{H}_{2}}C{{l}_{2}})\]
C) \[{{B}_{2}}{{H}_{6}}\] and alk. \[{{H}_{2}}{{O}_{2}}\]
D) \[{{O}_{3}}\text{/}Zn\]
Correct Answer: C
Solution :
\[KMn{{O}_{4}}\](alkaline) and \[Os{{O}_{4}}\text{/}C{{H}_{2}}C{{l}_{2}}\]are used for hydroxylation of double bond while\[{{O}_{3}}\text{/}Zn\] is used for ozonolysis. Therefore, the right option , is\[3C{{H}_{3}}CH=C{{H}_{2}}\xrightarrow{{{B}_{2}}{{H}_{6}}}{{(C{{H}_{3}}C{{H}_{2}}C{{H}_{2}})}_{3}}B\] \[\xrightarrow[NaOH]{{{H}_{2}}{{O}_{2}}}\underset{1-\text{propanol}}{\mathop{3C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH}}\,\]
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