A) \[KI\]
B) \[KCNS\]
C) \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]
D) \[B{{r}_{2}}\]
Correct Answer: A
Solution :
KI is added to old stocks of ethers when I is oxidised to \[{{I}_{2}}\] by ether peroxide which itself is reduced to ether\[2{{I}^{-}}\xrightarrow{{}}{{I}_{2}}+2{{e}^{-}}\]Ether peroxide\[+\,2{{e}^{-}}\xrightarrow{{}}\] ether\[+{{O}_{2}}\] In actual practice, the old stock of ether is repeatedly shaken with KI solution till it ceases to impart brown colour due to liberation of\[{{I}_{2}}\].
You need to login to perform this action.
You will be redirected in
3 sec
