A) \[41.7\,kJ\,mo{{l}^{-1}}\]
B) \[4.17\,kJ\,mo{{l}^{-1}}\]
C) \[417\,kJ\,mo{{l}^{-1}}\]
D) \[0.417\,kJ\,mo{{l}^{-1}}\]
E) \[4170\,kJ\,mo{{l}^{-1}}\]
Correct Answer: A
Solution :
\[\log \frac{{{k}_{2}}}{{{k}_{1}}}=\frac{{{E}_{a}}}{2.303R}\left[ \frac{{{T}_{2}}-{{T}_{1}}}{{{T}_{1}}\cdot {{T}_{2}}} \right]\] \[\frac{{{k}_{2}}}{{{k}_{1}}}=6,\] \[{{T}_{1}}=350K,\,{{T}_{2}}=400\,K\] \[\log 6=\frac{{{E}_{a}}}{2.303\times 8.314}\left[ \frac{400-350}{400\times 350} \right]\] \[0.7782=\frac{{{E}_{a}}}{2.303\times 8.314}\times \frac{50}{400\times 350}\] \[{{E}_{a}}=41721\,J\,mo{{l}^{-1}}\] \[=41.721\,kJ\,mo{{l}^{-1}}\]
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