A) \[18\,kg\text{-}{{m}^{2}}\]
B) \[1.8\,kg\text{-}{{m}^{2}}\]
C) \[2.5\,kg\text{-}{{m}^{2}}\]
D) \[9\,kg\text{-}{{m}^{2}}\]
E) \[0.9\,kg\text{-}{{m}^{2}}\]
Correct Answer: B
Solution :
Rotational kinetic energy of flywheel, \[K=360\,J\] Angular speed of flywheel, \[\omega =20\text{ }rad\text{/}s\] Rotational kinetic energy, \[k=\frac{1}{2}I{{\omega }^{2}}\] \[\therefore \] Moment of inertia, \[I=\frac{2K}{{{\omega }^{2}}}\] \[=\frac{2\times 360}{{{(20)}^{2}}}\] \[=1.8\,kg\text{-}{{m}^{2}}\]
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