A) \[CO=10\,L,\,C{{O}_{2}}=20L\]
B) \[{{O}_{2}}=10\,L,\,CO=20L\]
C) \[CO=20\,L,\,C{{O}_{2}}=10L\]
D) \[{{O}_{2}}=10\,L,\,C{{O}_{2}}=20L\]
E) \[{{O}_{2}}=10\,L,\,CO=20L\]
Correct Answer: A
Solution :
\[10\,L\]of\[{{O}_{2}}\]reacted with \[30L\]of \[CO\]at STP. \[\underset{20L}{\mathop{CO}}\,+\underset{10\,L}{\mathop{\frac{1}{2}{{O}_{2}}}}\,\xrightarrow[{}]{{}}\underset{20\,L}{\mathop{C{{O}_{2}}}}\,\]\[20\,L\,CO\]react with \[10\,L\,{{O}_{2}}\]to give \[20\,L\]of \[C{{O}_{2}}\]then left amount of\[CO\]will be (30 - 20) = \[10\text{ }L\]at the end of the reaction.
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