A) 1/49
B) 49
C) 7
D) \[{{49}^{2}}\]
E) 1/7
Correct Answer: E
Solution :
For the reaction \[{{N}_{2}}(g)+3{{H}_{2}}(g)\rightleftharpoons 2N{{H}_{3}}(g)\] \[{{K}_{c}}=\frac{{{[N{{H}_{3}}]}^{2}}}{[{{N}_{2}}]\,{{[{{H}_{2}}]}^{3}}}\] ?(i) For the reaction: \[N{{H}_{3}}(g)\rightleftharpoons \frac{1}{2}{{N}_{2}}(g)+\frac{3}{2}{{H}_{2}}(g)\] \[{{K}_{c}}=\frac{{{[{{N}_{2}}]}^{1/2}}{{[{{H}_{2}}]}^{3/2}}}{[N{{H}_{3}}]}\] ?(ii) From Eqs (i) and (ii) \[{{K}_{c}}=\sqrt{\frac{1}{{{K}_{c}}}}\] \[\therefore \,\,{{K}_{c}}=49\] \[\because \]\[{{K}_{c}}=\sqrt{\frac{2}{49}}\] \[\because \,{{K}_{c}}=\frac{1}{7}\]
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