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CMC Medical CMC-Medical VELLORE Solved Paper-2008

  • question_answer
    If 0.5 g of a solute (molar mass 100 g\[mo{{l}^{-1}}\]) in of solvent elevates the boiling point by 1K, the molar boiling point constant of the solvent is

    A)  2                                            

    B)  8

    C)  5                                            

    D)  0.5

    E)  10

    Correct Answer: C

    Solution :

                    By using the relation \[\Delta {{T}_{b}}=\frac{{{k}_{b}}\times {{w}_{B}}\times 1000}{{{M}_{B}}\times {{w}_{A}}}\] Here, \[\Delta {{T}_{b}}=1\,K,\]\[{{w}_{B}}=0.5g,\] \[{{w}_{A}}=25g\] \[{{M}_{B}}=100\,g\,\text{mo}{{\text{l}}^{-1}}\] \[\therefore \]                  \[1=\frac{{{k}_{b}}\times 0.5\times 1000}{100\times 25}\]                                 \[{{k}_{b}}=5\]


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