CMC Medical CMC-Medical VELLORE Solved Paper-2008

  • question_answer
    The half cell reaction with their standard electrode potentials are \[P{{b}^{2+}}(aq)+2{{e}^{-}}t\xrightarrow{{}}Pb(s);\]\[E{}^\circ =-\,0.13\,V\] \[A{{g}^{+}}(aq)+{{e}^{-}}\xrightarrow{{}}Ag(s);\]   \[E{}^\circ =+\,0.80\,V\] What is the emf of the cell?

    A)  \[-\,0.93\,\,V\]                

    B)  \[+\,0.93\,V\]

    C)  \[+\,0.67\,V\]                                  

    D)  \[-\,0.67\,\,V\]

    E)  None of these

    Correct Answer: B

    Solution :

                    \[Pb(s)+2A{{g}^{+}}(aq)\xrightarrow{{}}P{{b}^{2+}}(aq)+2Ag(s)\] \[E_{cell}^{{}^\circ }=E_{cathode}^{{}^\circ }-E_{anode}^{{}^\circ }\]         \[=+\,0.80-(-0.13)\] \[E_{cell}^{{}^\circ }=0.93\,V\]


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