A) \[S{{O}_{2}}\]
B) \[O{{F}_{2}}\]
C) \[SC{{l}_{4}}\]
D) \[S{{O}_{3}}\]
Correct Answer: B
Solution :
\[O{{F}_{2}}\]dissolves in water but does not give any oxyacid solution. While \[S{{O}_{2}},SC{{l}_{4}}\] and\[S{{O}_{3}}\] give oxyacid solution in water. \[S{{O}_{2}}+{{H}_{2}}O\xrightarrow{{}}\underset{\begin{smallmatrix} sulphurous \\ \,\,\,\,\,acid \end{smallmatrix}}{\mathop{{{H}_{2}}S{{O}_{3}}}}\,\] \[SC{{l}_{4}}+3{{H}_{2}}O\xrightarrow[{}]{{}}\underset{\begin{smallmatrix} sulphurous \\ \,\,\,\,\,acid \end{smallmatrix}}{\mathop{{{H}_{2}}S{{O}_{3}}}}\,+4HCl\] \[S{{O}_{3}}+{{H}_{2}}O\xrightarrow{{}}\underset{sulphuric\,acid}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,\]
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