CMC Medical CMC-Medical VELLORE Solved Paper-2009

  • question_answer
    The half-life of radioactive material is 3 h. If the initial amount is 300 g. Then after 18 h, it will remain

    A)  4.69 g                                  

    B)  46.8 g

    C)  9.375 g                                

    D)  93.75 g

    Correct Answer: A

    Solution :

                    Number of half-lives \[n=\frac{t}{{{t}_{1/2}}}=\frac{18h}{3h}=6\] Using the relation \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\]                 \[N=300\times {{\left( \frac{1}{2} \right)}^{6}}\] Hence,  \[N=300\times \frac{1}{64}=4.69\,g\]


You need to login to perform this action.
You will be redirected in 3 sec spinner