A) \[{{C}_{2}}{{H}_{6}}\]
B) \[{{C}_{6}}{{H}_{6}}\]
C) \[CH\equiv CH\]
D) \[C{{H}_{3}}OH\]
Correct Answer: D
Solution :
\[C{{H}_{3}}OH\] (methyl alcohol) among the given compounds, has the highest tendency to donate a proton, hence it is the strongest acid. \[\underset{methanol}{\mathop{C{{H}_{3}}OH}}\,\rightleftharpoons \underset{\begin{smallmatrix} methoxide \\ \,\,\,\,\,\,\,ion \end{smallmatrix}}{\mathop{C{{H}_{3}}{{O}^{-}}}}\,+{{H}^{+}}\]
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