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CMC Medical CMC-Medical VELLORE Solved Paper-2009

  • question_answer
    0.126 g of an acid is titrated with 0.1 N 20 mL of an base. The equivalent weight of the acid is

    A)  63                                         

    B)  50   

    C)  53                                         

    D)  23

    Correct Answer: A

    Solution :

                    We know that, \[w=\frac{ENV}{1000}\] \[\therefore \] Eq. wt. of acid\[=\frac{w\times 1000}{NV}\] \[=\frac{0.126\times 1000}{0.1\times 20}=63\]


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