A) Mg
B) Zn
C) Cu
D) Hg
Correct Answer: A
Solution :
Mg, being the most reactive metal, gives\[{{H}_{2}}\]gas with dilute \[HN{{O}_{3}}\]while all other given elements react differently with dilute\[HN{{O}_{3}}\]. \[Mg+\underset{dilute}{\mathop{2HN{{O}_{3}}}}\,\xrightarrow{{}}Mg{{(N{{O}_{3}})}_{2}}+{{H}_{2}}\] \[4Zn+\underset{dilute}{\mathop{10HN{{O}_{3}}}}\,\to 4Zn{{(N{{O}_{3}})}_{2}}+{{N}_{2}}O+5{{H}_{2}}O\] \[3Cu+\underset{dilute}{\mathop{8HN{{O}_{3}}}}\,\to 3Cu{{(N{{O}_{3}})}_{2}}+2NO+4{{H}_{2}}O\] \[6Hg+\underset{dilute}{\mathop{8HN{{O}_{3}}}}\,\to 3H{{g}_{2}}{{(N{{O}_{3}})}_{2}}+2NO+4{{H}_{2}}O\]
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