2. Solved Papers
  3. CMC Medical

CMC Medical CMC-Medical VELLORE Solved Paper-2010

  • question_answer
    Equation of a progressive wave is given by \[y=0.2\cos \pi \left( 0.04t+0.02x-\frac{\pi }{6} \right)\] The distance is expressed in cm and time in second. What will be the minimum distance between two particles having the phase difference of\[\frac{\pi }{2}\]?

    A)  4 cm                                     

    B)  8 cm

    C)  25 cm                                  

    D)  12.5 cm

    E)  None of these

    Correct Answer: C

    Solution :

                    Comparing with \[y=a\,\text{cos}\left( \omega t+kx-\phi  \right)\] We get,     \[k=\frac{2\pi }{\lambda }=0.02\,\pi \] \[\Rightarrow \]               \[\lambda =100\,km\] Also, it is given that phase difference between particles \[\Delta \phi =\frac{\pi }{2}.\] Hence, path difference between them \[\Delta x=\frac{\lambda }{2\pi }\times \Delta \phi \] \[=\frac{\lambda }{2\pi }\times \frac{\pi }{2}\] \[=\frac{\lambda }{4}=\frac{100}{4}\] = 25 cm


You need to login to perform this action.
You will be redirected in 3 sec spinner