CMC Medical CMC-Medical VELLORE Solved Paper-2010

  • question_answer
    When an electron in hydrogen atom is excited, from its 4th to 5th stationary orbit the change in angular momentum of electron is (Plancks constant\[h=6.6\times {{10}^{-34}}J\text{/}s\])

    A)  \[4.16\times {{10}^{-34}}\,J\text{-}s\]  

    B)  \[3.32\times {{10}^{-34}}\,J\text{-}s\]

    C)  \[1.05\times {{10}^{-34}}\,J\text{-}s\]  

    D)  \[2.08\times {{10}^{-34}}\,J\text{-}s\]

    E)  None of these

    Correct Answer: C

    Solution :

                     Change in the angular momentum, \[\Delta L={{L}_{2}}-{{L}_{1}}\] \[=\frac{{{n}_{2}}h}{2\pi }-\frac{{{n}_{1}}h}{2\pi }\] \[\Delta L=\frac{h}{2\pi }({{n}_{2}}-{{n}_{1}})\] \[=\frac{6.6\times {{10}^{-34}}}{2\times 3.14}(5-4)\] \[=1.05\times {{10}^{-34}}\,J\text{-}s\]


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