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CMC Medical CMC-Medical VELLORE Solved Paper-2010

  • question_answer
    The current gain \[\alpha \] of a transistor is 0.95. The change in emitter current is 10 mA. The change in base current is

    A)  9.5 mA                                

    B)  0.5 mA

    C)  10.5 mA              

    D)  \[\left( \frac{200}{19} \right)\]mA

    E)  None of these

    Correct Answer: B

    Solution :

                    Current gain \[\alpha =\frac{{{i}_{C}}}{{{i}_{E}}}=\frac{{{i}_{E}}-{{i}_{B}}}{{{i}_{E}}}\] \[\therefore \]  \[0.95=\frac{10-{{i}_{B}}}{10}\]                 \[10-{{i}_{B}}=0.95\times 10\]                 \[10-{{i}_{B}}=9.5\]                 \[{{i}_{B}}=10-9.5\]                 \[=0.5\,mA\]


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