A) \[CH\]
B) \[{{C}_{2}}{{H}_{3}}\]
C) \[C{{H}_{2}}\]
D) \[C{{H}_{3}}\]
E) None of these
Correct Answer: C
Solution :
\[%\,C=\frac{12}{44}\times \frac{12.571}{4.0}\times 100=85.7\] \[%H=\frac{2}{18}\times \frac{5.143}{4.0}\times 100=14.3\] The mole ratio of C to H is \[\frac{85.7}{12}:\frac{14.3}{1}\] \[=7.14:14.3=1:2=C{{H}_{2}}\]
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