A) \[KMn{{O}_{4}}\]
B) \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\]
C) \[Cr{{O}_{3}}\]
D) PCC (pyridine chloro chromate)
E) None of the above
Correct Answer: D
Solution :
Strong oxidising agents such as\[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\]convert alcohol directly to carboxylic acid. However oxidation can be stopped at aldehyde stage by using \[Cr{{O}_{3}}\]in anhydrous medium. PCC (pyridinium chloro chromate) is a better oxidising agent because it stopped the oxidation of primary alcohol at aldehydic stage. \[RC{{H}_{2}}OH\xrightarrow{PCC}RCHO\]
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