CMC Medical CMC-Medical VELLORE Solved Paper-2010

  • question_answer
    \[{{K}_{p}}\] for the reaction, \[{{N}_{2}}{{O}_{4}}(g)\rightleftharpoons 2N{{O}_{2}}(g)\] is 0.157 atm at \[27{}^\circ C\] and 1 atm pressure. \[{{K}_{c}}\]for this reaction is

    A)  \[6.37\times {{10}^{-3}}\]                           

    B)  \[4.29\times {{10}^{-3}}\]

    C)  \[5.62\times {{10}^{-3}}\]                           

    D)  \[4.37\times {{10}^{-3}}\]

    E)  None of these

    Correct Answer: A

    Solution :

                    \[\Delta {{n}_{g}}={{n}_{p}}-{{n}_{r}}=2-1=1,\] \[{{K}_{c}}=\frac{{{K}_{p}}}{{{(RT)}^{\Delta {{n}_{g}}}}}\] \[=\frac{(0.157\,atm)}{{{(0.0821\,\,L\,\,atm\,{{K}^{-1}}\,mo{{l}^{-1}}\,\times \,300\,K)}^{1}}}\] \[=6.37\times {{10}^{-3}}\,mol\,{{L}^{-1}}\]


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