A) ethyl bromide
B) iso-propyl bromide
C) vinyl bromide
D) n-propyl bromide
E) t-butyl bromide
Correct Answer: E
Solution :
\[{{S}_{N}}1\]mechanism involves formation of carbocation intermediate. Hence, the species which gives the most stable carbocation readily undergoes \[{{S}_{N}}1\] mechanism, t-butyl bromide gives the most stable carbocation, i.e., \[3{}^\circ \]carbocation, so it readily undergoes \[{{S}_{N}}1\]reaction.
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