A) \[SnC{{l}_{2}}/HCl\]
B) \[NaB{{H}_{4}}/ether\]
C) \[{{H}_{2}}/Pd\]
D) \[{{N}_{2}}{{H}_{4}}/{{C}_{2}}{{H}_{5}}ONa\]
E) \[{{B}_{2}}{{H}_{6}}/{{H}_{3}}{{O}^{+}}\]
Correct Answer: E
Solution :
Carboxylic acids when treated with either diborane or LAH, get reduced to primary alcohols. Diborane is a better reagent than LAH for such conversion, as it does not affect other functional groups such as ester, nitro, halo etc. \[R-COOH+{{B}_{2}}{{H}_{3}}\xrightarrow[{{H}_{3}}{{O}^{+}}]{}R-C{{H}_{2}}OH\]
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