A) 0.4 V
B) 0.6 V
C) 226 V
D) 2.26 V
E) 22.6 V
Correct Answer: C
Solution :
\[{{e}_{\max }}=NBA\omega \] \[\therefore \]\[{{e}_{\max }}=30\times 1\times \left( \frac{400}{10000} \right)\times \left( 1800\times \frac{2\pi }{10} \right)\] \[{{e}_{\max }}=226\,V\]
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