CMC Medical CMC-Medical VELLORE Solved Paper-2011

  • question_answer
    A bulb has specifications of 1 kW and 250 V, the resistance of bulb is

    A)  625\[\Omega \]                              

    B)  0.25\[\Omega \]

    C)  6.25\[\Omega \]             

    D)  62.5\[\Omega \]

    E)  2.5\[\Omega \]

    Correct Answer: D

    Solution :

                                    \[P=\frac{{{V}^{2}}}{R}\] \[R=\frac{{{V}^{2}}}{P}\] \[R=\frac{250\times 250}{1000}=62.5\,\Omega \]


You need to login to perform this action.
You will be redirected in 3 sec spinner