A) \[\alpha =\frac{\beta }{1-\beta }\]
B) \[\beta =\frac{\alpha }{1-\alpha }\]
C) \[\alpha =\frac{\beta }{1+\beta }\]
D) \[1-\alpha =\frac{1}{1+\beta }\]
E) \[\beta =\alpha (1+\beta )\]
Correct Answer: A
Solution :
As \[\beta =\frac{\alpha }{1-\alpha }\] \[\therefore \] \[\alpha =\frac{\beta }{1+\beta }\] Also, \[1-\alpha =\frac{1}{1+\beta }\]
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